Thanks for the answers. NuSiEr, you hit my question right on the nail. Hopefully someone with a already well tuned car will buy the EBL and dyno it at booth max boost and 6 psi. Tell then I'll wait tell I get enough money to get a EBL. Thanks again.
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Thanks for the answers. NuSiEr, you hit my question right on the nail. Hopefully someone with a already well tuned car will buy the EBL and dyno it at booth max boost and 6 psi. Tell then I'll wait tell I get enough money to get a EBL. Thanks again.
KSIG, : [quote] Now I know that if you were to be running the boost level at lets say the stock 6 psi with the EBL and a 9 pound pulley some of the air is entering the engine through the bypass valve (cooler air) and some through the charger (hotter air). Now the air that is going through the charger is hotter then if is was running at the stock 6 psi speed but it is being mixed in with cooler air that is coming in through the bypass valve. [quote/]
surely when the bypass opens at boost, air will flow from the plenum back through the blower (high pressure to lower pressure), and the intake temps will gain a *bit* more heat as the rotors continually beat the crap out of this re-circulated air ? Going back to old Eaton math threads here, half the heat of the intake charge is from boyles law (compressing air makes it hotter), and the other half is caused by Eaton blowers being '0.5 efficient' (argue this your selves) which doubles the Boyles law figure for temperature rise with increasing boost.
I guess what I am trying to suggest is that by spinning the blower for 12 psi and boosting say 8 psi, does temperature rise equal the Boyles law figure for 8psi, and the mechanical efficiency figure for friction heated air at 12psi ???
Throwing a few numbers at it, it looks to give the same temps as boosting at 10 psi
Now I get to think about it : crank HP required to drive the blower - using the above figures again, boosting 8psi on a 12 psi pulley, would the crank hp required be the hp for 8psi (the work of compressing to 8psi) or the higher rate for 12psi (the work of spinning the rotors to say, 14000 rpm instead of 9500 rpm) ???
Before any one gets their panties in a bind, these are hypothetical figures, to illustrate a point, and help generate a discussion on the principals involved with 'pressure manipulation'. With a little bit of luck I havent killed this thread stone dead.... http://www.hostboard.com/ubb/wink.gif